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  #16  
Old 10-27-2018, 03:40 AM
stanron stanron is offline
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Rather than do a sneaky edit I'll do a new post to amend my last one. The B chord actually starts on beat three not beat 2. Half a bar of E and half a bar of B or B7.
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  #17  
Old 10-28-2018, 03:46 AM
JonPR JonPR is offline
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Quote:
Originally Posted by RockyRacc00n View Post
I was strictly following the structure of the 12 bar blues and expected all of the last bar to be in B.
That's very rarely how it works. Almost every time, the first beat of the 12th bar is the tonic. Then it goes to the V immediately after - sometimes on beat 2, sometimes on the "and of 1", sometimes as late as beat 3. And sometimes never (sometimes it stays on the tonic all the way, with no turnaround).

If you see a blues chart with the whole of bar 12 on the V chord, that's just a simplification (and a crude one at that). There is nothing "strict" about the blues (...man).
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  #18  
Old 10-29-2018, 12:49 PM
RockyRacc00n RockyRacc00n is offline
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Quote:
Originally Posted by JonPR View Post
That's very rarely how it works. Almost every time, the first beat of the 12th bar is the tonic. Then it goes to the V immediately after - sometimes on beat 2, sometimes on the "and of 1", sometimes as late as beat 3. And sometimes never (sometimes it stays on the tonic all the way, with no turnaround).

If you see a blues chart with the whole of bar 12 on the V chord, that's just a simplification (and a crude one at that). There is nothing "strict" about the blues (...man).
Yes. After some closer look at the material I am studying, I see what you are saying. Thank you.
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  #19  
Old 10-29-2018, 08:45 PM
jomaynor jomaynor is offline
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While you can count a slow blues like this with 4/4 triplets, I prefer to think of it as being in 12/8, and I count the time in 2 eighth note groups of 6:
1-2-3-4-5-6, 1-2-3-4-5-6 (the backbeats are on the "4"s this way)

Or you could count it once up to 12:
1-2-3-4-5-6-7-8-9-10-11-12 (backbeats are on the "4" and the "10" this way)
But I like to avoid non-single syllable numbers when counting, so I prefer the first way: 2 groups of 6 per bar.

In 12/8 time, therefore, this turnaround is 2 bars long:
1) 123456-123456
2) 123456-123456
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