Quote:
Originally Posted by LouieAtienza
The radius at the end is predetermined because the width (chord) and height (sagitta) are defined...
Or are you trying to reel me in?  |
Now then Louie, would I do a thing like that
...although I
did have you in mind as i was typing the post.
Quote:
Originally Posted by rick-slo
I don't have the calculations at hand but you are looking for equal sagittal depth assuming the fretboard thickness was not tapered to begin with.
However question: aren't conical fretboards not truly conical but instead have multi-radiuses which are blended one into another?
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Yes, the fretboard starts off at a constant thickness, but tapered to the required widths (which will be 1.75" at the nut and 2.5" at the end.
The fretboard surface
is actually a true section of a cone.
My nut radius will be 14", and it works out that with a 1.75" wide nut and a 2.5" wide fretboard end, the radius at the end will be 20" exactly.