So I’ve been giving some thought to the rule that however much you want to take down at the 12th, you double and that is the amount to take off at the saddle.
If the 12th is the midpoint between the nut and saddle, someone had pointed out to me that this relationship can be summarized thus: the change is the inverse of the ratio of the distance from the saddle to the fret in question versus the entire length to the nut. In the case of the 12th, it’s ½ the distance and therefore you shave off 2/1 times.
Out of curiosity would this technically apply to the nut as well? Granted, of course the proper way is how it’s been described here. But mathematically, would that still hold?
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